The seven-millionth term of A157711

The sum of the first 4740 prime counts of A383675 is 6998767. The sum of the first 4741 prime counts is 7001942. Hence, the seven-millionth term of A157711 is a 4741-digit integer:

6998768 10^4740+10^43+10^40+1
6998769 10^4740+10^92+10^83+1
6998770 10^4740+10^121+10^40+1
6998771 10^4740+10^122+10^28+1
6998772 10^4740+10^202+10^64+1
...
6999995 10^4740+10^2934+10^1719+1
6999996 10^4740+10^2936+10^119+1
6999997 10^4740+10^2936+10^1685+1
6999998 10^4740+10^2936+10^1810+1
6999999 10^4740+10^2936+10^2873+1
7000000 10^4740+10^2937+10^822+1
7000001 10^4740+10^2938+10^167+1
7000002 10^4740+10^2938+10^1135+1
7000003 10^4740+10^2940+10^1593+1
7000004 10^4740+10^2940+10^1653+1
7000005 10^4740+10^2942+10^1791+1
...
7001938 10^4740+10^4738+10^1605+1
7001939 10^4740+10^4738+10^3141+1
7001940 10^4740+10^4738+10^4149+1
7001941 10^4740+10^4739+10^726+1
7001942 10^4740+10^4739+10^1644+1

A157711(1*10^6) = 10^1793+10^673+10^615+1 [2025 June 19]
A157711(2*10^6) = 10^2535+10^1160+10^398+1 [2025 July 21]
A157711(3*10^6) = 10^3103+10^2747+10^859+1 [2025 September 10]
A157711(4*10^6) = 10^3583+10^3040+10^2776+1 [2025 December 7]
A157711(5*10^6) = 10^4006+10^2673+10^876+1 [2026 February 14]
A157711(6*10^6) = 10^4388+10^3968+10^1845+1 [2026 June 7]
A157711(7*10^6) = 10^4740+10^2937+10^822+1 (above)
A157711(8*10^6) ~ 10^5068

I'll continue to update (here, until the next millionth is reached) my current plot of A383675:

A383675 to n=4767; max=(4761,3870) [updated October 30]  click to enlarge