This is a

*compressed*version of my previous graph as only one of every one thousand points is shown and connected. I have added an x=y line to indicate where along the walk the accumulated number of ones and twos might be equal. (950,2678) is shown as a black dot. Starting at that point — in cyan — I have*continued*the walk (a bit of the left and a lot of the right of it has been cropped). The*full*walk to 8 billion looks like this:
A hint of orange near the origin betrays the change in scale of the continuation. After step 8 billion we have reached (42488,102078), also marked by a black dot. Which is to say that we have a digit deficit at this point of 102078 zeros and 59590 twos! I counted 96619 times that the number of ones and twos were exactly equal. And we are left with 0, 15, and 18 initial ternary-π digits as the only known instances where the number of all three digits are exactly equal.

**Addendum:**I have upped the walk from 8 billion steps to 10 billion steps, where we have reached (35427,93367). I'm also reworking the graphics, which I will showcase in a future article.

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